The Earth as a particle accelerator
Almost all trials to calculate the speed of neutrinos, presented so far, we believe that there was loss of speed for error calculations. (A lot of pretense, no?)
Now consider that, in fact, there was an increase of speed in these particles.
Without the use of elaborate hypotheses that "explain" the gain in speed of neutrinos, we know that the laboratory is in the Italian underground.
We found no difference in elevation value of these laboratories in the network, but we know that when a body approaches the radius of the Earth, it loses potential energy and gains kinetic energy, otherwise the law of conservation of energy is violated.
Ok, above our present problem in proportional scale. The distance between the laboratory and the Swiss Italian laboratory is approximately 730 km. This represents an arc of 6 degrees.
To better visualization the problem, we change the aspect ratio of the original situation, but keep the numerical values closer to the real, as shown above.
We believe that the Swiss lab is the 6 300 000 m from the center of the Earth.
As we know that the Italian laboratory is closer to the center of the earth, and to assure that the speed gain of neutrinos during their "down", we, from the known data, deducing the value of "h".
According to data collected on the Web, neutrinos from Switzerland at a speed very close to "c", ie, the speed of light in vacuum.
c = 299799 846.741 m / s
The gain in speed of arrival of neutrinos in the Italian laboratory, after a voyage of 732 000 m was approximately 388.741 7 663 m / s.
Therefore, the speed of arrival of neutrinos became:
vn = c + 7 663 388.741 m / s = 299 807 235.5 m / s
We start now to the calculation of h:
c ^ 2 / r = (vn) ^ 2 / (r-h)
See board below:
310 meters deep, a very interesting result.